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x^2-5x-5000=0
a = 1; b = -5; c = -5000;
Δ = b2-4ac
Δ = -52-4·1·(-5000)
Δ = 20025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{20025}=\sqrt{225*89}=\sqrt{225}*\sqrt{89}=15\sqrt{89}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-15\sqrt{89}}{2*1}=\frac{5-15\sqrt{89}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+15\sqrt{89}}{2*1}=\frac{5+15\sqrt{89}}{2} $
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